QuizSagar
4 years ago Like 232906
Questions 823
Contests 7
The time required to convert a k-bit integer to its representation in the base 10 in terms of big-O notation is
- O(log2 n)
- O(logn)
- O(log2 2n)
- O(2logn)
- option1
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The estimated computations required to crack a password of 6 characters from the 26 letter alphabet is-
- 11881376
- 308915776
- 456976
- 8031810176
- option2
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Each char. have max 26 possibility so, 26^6=308915776
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The DES Algorithm Cipher System consists of ____________rounds (iterations) each with a round key
- 12
- 18
- 9
- 16
- option4
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In the DES algorithm the round key is __________ bit and the Round Input is ____________bits.
- 48,32
- 64,32
- 56,24
- 32,32
- option1
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In what proportion must rice that cost 20/kg be mixed with rice that cost 25/kg so that the mixture is worth 22/kg?
- 1:3
- 3:1
- 2:3
- 3:2
- option4
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किस दर्पण की फोकस दूरी ऋणात्मक होती है?
- समतल दर्पण
- अवतल दर्पण
- उत्तल दर्पण
- इनमें से कोई नहीं
- option2
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Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is
- 3:4
- 4:3
- 16:9
- 2:3
- option2
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Ratio of the speed if two bodies towards each other is √speed of a : √speed of b
=√16:√9 = 4:3
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Two trains, one from Siwan to Patna and the other from Patna to Siwan, start simultaneously. After they meet, the trains reach their destinations after 4 hours and 3 hours respectively. The ratio of their speeds is
- √3:4
- 4:√3
- 4:3
- 2:√3
- option4
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Ratio of the speed if two bodies towards each other is √speed of a : √speed of b
=√4:√3 = 2:√3
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Two cars start at the same time from the same location and go in the same direction. The speed of the first car is 50 km/h and the speed of the second car is 60 km/h. The number of hours it takes for the distance between the two cars to be 20 km is
- 1
- 2
- 3
- 6
- option2
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Time =Total Distance/Relative Speed
Time=20km÷(60-50)km/h=2h
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A tiger is 50 leaps of its own behind a deer. The tiger takes 5 leaps per minute to the deer's 4. If the tiger and the deer cover 8 metre and 5 metre per leap respectively, what distance in metres will the tiger have to run before it catches the deer?
- 400
- 800
- 100
- 200
- option2
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Total Distance=50 leep of tiger speed=50*8=400,
Tiger Speed=5leeps/min=5*8m=40m,
Deer Speed=4leeps/min=4*5m=20m
Time=Total Distance÷Relative speed
=400m÷(40-20)m/min=20min,
Total distance cover by Tiger is,
=Speed*Time=40m/min*20min=800m
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